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mulDiv returns 0 if numerator is 0 and denominator isn't:
* Otherwise overflow checks result in divide by 0. * If denominator is 0, let the divide by 0 exception throw. * Move mulDiv out of STAmount
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@@ -1275,40 +1275,6 @@ divRound (STAmount const& num, STAmount const& den,
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return result;
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}
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// compute (value)*(mul)/(div) - avoid overflow but keep precision
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std::uint64_t
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mulDiv(std::uint64_t value, std::uint64_t mul, std::uint64_t div)
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{
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lowestTerms(value, div);
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lowestTerms(mul, div);
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if (value < mul)
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std::swap(value, mul);
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const auto max = std::numeric_limits<std::uint64_t>::max();
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if (value > max / mul)
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{
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value /= div;
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if (value > max / mul)
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Throw<std::overflow_error> ("mulDiv");
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return value * mul;
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}
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return value * mul / div;
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}
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// compute (value)*(mul)/(div) - avoid overflow but keep precision
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std::uint64_t
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mulDivNoThrow(std::uint64_t value, std::uint64_t mul, std::uint64_t div)
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{
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try
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{
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return mulDiv(value, mul, div);
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}
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catch (std::overflow_error)
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{
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return std::numeric_limits<std::uint64_t>::max();
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}
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}
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NetClock::time_point
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STAmountCalcSwitchovers::enableUnderflowFixCloseTime ()
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{
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